In an experiment on measurements of emf of a cell by a potentiometer, the balancing length for a cell of emf E and internal resistance r is found to be λ . Now if another cell of emf E and internal resistance 2r is connected in parallel to the first cell and balancing length determined, then the balancing length will be-
A
λ
B
2 λ
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
Since potentiometer doesn't draw any current to measure the emf of the cell, the balancing length will remain the same. balancing length 
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